Question

What is (a) the highest, (b) the lowest total resistance that can be secured by combinations of four coils of resistance 4ohm, 8ohm, 12 ohm, 24 ohm? ​

Answer 1

Answer:

R, = 4 Q R2 = 8 0 R3 = 12 Q R4 = 24 Q Solution :- (a) The highest resistance is when the resistances are connected in series. Total resistance in series = R, + R2 + R3 + R4 Total resistance in series = 4 + 8 + 12 + 24 Total resistance in series = 48 Q Hence, the highest resistance is 48 Q. (b) The lowest resistance is when the resistances are connected in parallel 1/R = 1/R, + 1/R2 + 1/R3 + 1/R4 %3D 1/R = 1/4 + 1/8 + 1/12 + 1/24 1/R = 12/24 1/R = 1/2 Q R = 20 Hence, the lowest resistance is 2 Q.

Answer 2

Explanation:

What is (a) the highest, (b) the lowest total resistance that can be secured by combinations of four coils of resistance 4 Ω, 8 Ω, 12 Ω, 24 Ω? R = 4 + 8 + 12 + 24 = 48 Ω.