Question

what is a velocity of an object of mass 1kg which has 200 j of kinetic energy​

Answer 1

$\huge\bf { \red S \green O \pink L \blue U \orange T \purple I \red O \pink N \green{...}}$

$\large \implies \boxed{\bf \orange{Energy = \dfrac{1}{2} {mv}^{2} } }$

$\implies \sf200 = \dfrac{1}{2} \times 1 \times {v}^{2}$

$\implies \sf {v}^{2} = 200 \times 2$

$\implies \sf {v}^{2} = 400$

$\implies \sf v = \sqrt{400}$

$\large\implies \boxed{ \sf \red{ v = 20 \: m {s}^{ - 1} }}$

Answer 2

Explanation:

$ke = {v}^{2} m \div 2$

${v}^{2} = 2ke \div m$

${v}^{2} = 2 \times 200 = 400$

thus,

v=20m/s