what is a3 +b3 +c3-3abc
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3
Answer:
a³ + b³ + c³ -3abc = (a + b +c)( a² + b² + c² -ab - bc - ca).
important points*
1. if a + b + c = 0 then,
a³ + b³ + c³ = 3abc
2. if a = b = c , then
a³ + b³ + c³ = 3abc
Answered by
0
Answer:
a³+b³+c³-3abc = (a+b+c) (a²+ b²+ C²-ab-bc-ca)
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