Question

What is acceleration of block when block is of 5kg and inclined by angle of 37 degree and force 50n and friction force 0.5?

Answer 1

mass = 5 kg

theta = 37°

two components

horizontally = f cos theta

vertically = f sin theta

so,

Normal reaction = f sin theta

i.e. 5g. = f sin theta

so,

horizontally = f cos theta

= 50*cos 37°

= 50 * 4/5

= 40

so,

40 - 0.5 = 5a

39.5 = 5a

then,

a = 39.5/5

= 7.9 m/s²