what is altitude of an equilateral triangle of each side 6 CM
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1.Draw any line l.
2.Take any point M on it and draw a line p perpendicular to l.
3.With M as centre, cut off MC = 6 cm
4.At C, with initial line CM construct angles of measures 30° on both sides and let these lines intersect line l in A and B. Thus, ΔABC is the required triangle.
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