Chemistry, asked by katukojwalasanp9wi3a, 9 months ago

What is amount of caco3 is needed to produce 336 gm of Cao if % yield of reaction is 60%

Answers

Answered by gopikrishnamanaidu

0

Answer:

Answer :

A

Solution :

CaCO3(s)→CaO(s)336kg+CO21g

Moles of CaO = 33656×103=6×103

Mass of CaCO3 required =6×103×10060×100=103kg

Explanation:

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