Question

What is an argument of a complex number z =-i+1/i​

Answer 1

Step-by-step explanation:

-i+1/i

-(i)²+1/i

{1+1}/i

2/i

2i/i²

-2i

Answer 2

Answer:

arg(z)=π/4

Step-by-step explanation:

$z = \frac{( - i + 1) \times i}{i \times i}$

now,

$= \frac{1 + i}{ - 1}$

$= - 1 - i$

as

$\sqrt[2]{i } = - 1$

$arg(z) = { \tan}^{ - 1} \binom{x}{y}$

$z = x + yi$

where ; x = -1 and y = -1

tan^-1 = (-1/-1) = π/4