What is an equation in point-slope form for the line that passes through the points (4,−1) and (−3,4) ?
A: y+4=−5/7(x+3)
B: y+4=5/7(x+3)
C: y−3=−5/7(x+4)
D: y−4=−5/7(x+3)
Answers
Answered by
4
very simple !!
first find the slope
so slope comes out to be
=> y2-y1 / x2-x1
=> 4-(-1) / -3-(4)
5/-7
or => -5/7
now ,
equation of the line
y - (4) = -5/ 7 ( x +3 )
y -4 = -5/7 ( x +3 )
hope it help you !!
thanks !!
first find the slope
so slope comes out to be
=> y2-y1 / x2-x1
=> 4-(-1) / -3-(4)
5/-7
or => -5/7
now ,
equation of the line
y - (4) = -5/ 7 ( x +3 )
y -4 = -5/7 ( x +3 )
hope it help you !!
thanks !!
Answered by
4
Hey!!
Equation of line passing through points ( 4, -1 )
and ( -3,4 ) having slope m is given by.
y -y1 = m ( x -x1 )
y1 = 4. ,. x1 = -3. and m. = -4 -1 / 3 +4
y -4 = - 5 / 7 ( x +3)
Have a nice time.
Equation of line passing through points ( 4, -1 )
and ( -3,4 ) having slope m is given by.
y -y1 = m ( x -x1 )
y1 = 4. ,. x1 = -3. and m. = -4 -1 / 3 +4
y -4 = - 5 / 7 ( x +3)
Have a nice time.
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