What is an equation of the line that is parallel to y = 3x – 8 and passes through the point (4, –5)?
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Line y=3x-8 (let this be line PQ) is parallel to the line suppose AB
Thus,
Slope of PQ(m1) = Slope of AB(m2)
By formula y= mx+ c,
we get the value of m1 as 3 ( from PQ)
Now as per the question the point ( 4, -5) passes through AB thus,
By the equation of a line
(y-y1)/(x1-x2) = m2
(y-(-5))/ (x-4) =3
You get ,
The equation as
y=3x- 17
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