Question

what is an equation of the line that is perpendicular to y-3 = -4 (x+2) and passes though the point (-5,7)

Answer 1

Answer:

equation of the line

y-3=-4x-8

4x+y=-8+3

4x+y=-5

4x+y+5=0

Answer 2

Answer: y=x/4+33/4

Step-by-step explanation:

y-3=-4(x+2)

y=-4(x+2)+3

y=-4x-8+3

y=-4x-5

A line perpendicular to this equation will have a slope of

$\frac{1}{4} x$

And since it passes through (-5, 7), the equation should be

$y = \frac{1}{4} x + \frac{33}{4}$