Question

What is an = ? if a = 3.5 , d = 0 and n = 105

Answer 1

3.5

Here,

a = 3.5 ,

d = 0 ,

n = 105.

Therefore,

a(n) = a + (n-1)d .

a(n) = 3.5 + (105-1)0.

a(n) = 3.5 + 0 .

a(n) = 3.5

So, the 105th term of this AP is 3.5 .

______________

Answer 2

Answer:-

$\small\sf{a=3.5}$

$\small\sf{d=0}$

$\small\sf{n=105}$

━━━━━━━━━━━━━━━

$\small\sf{So\:putting\:the\:values}$

$\small\sf{an=a+(n-1)d}$

$\small\sf{an=3.5+(105-1)(0)}$

$\small\sf{an=3.5+0}$

$\small\sf{an=3.5}$