Question

What is an ordered pair??

The number of ordered pairs (a , b) of natural numbers such that $a^b+b^a = 100$ is:


A) 1

B) 2

C) 3

D) 4

Answer 1

Answer:

4

Step-by-step explanation:

There are two (1,99) and (99,1)

[in fact for any number, a^b + b^a = n the pairs are (1,n-1) & (n-1, 1)]

in this case , by hit and trial there is two more which are (2,6) and (6,2)

Answer 2

The answer is 4 because a^a+b^b