Question

what is angle between i cap +j cap+k cap and jcap​

Answer 1

Answer:

a⋅b=∥a∥∥b∥cosθ

For your two vectors, this becomes:

(i^+j^)⋅(j^+k^)=∥i^+j^∥∥j^+k^∥cosθ

⟹(1)(0)+(1)(1)+(0)(1)=(12+12−−−−−−√)(12+12−−−−−−√)cosθ

⟹1=2–√2–√cosθ

⟹1=2cosθ

⟹12=cosθ

⟹θ=cos−1(12)

⟹θ=60°=π3

radians

Explanation: