Question

what is angle of projectile of a projected with velocity 30m/s so that the horozontal range is 45 m.( g=10m/s​

Answer 1

Answer:

What are the two angles of projection of a projectile projected with velocity of 30 m//s, so that the horizontal range is 45 m. Take, g= 10 m//s^(2). 2θ=30∘or15∘orθ=15∘or75%(∘).