What is answer of the question
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1
rs 1000. a=200,d =50,n=17
tn=a+(n-1)d
t17=200+(17-1)x 50
=200+16 X 50
=200+800
=1000
TheLostMonk:
really,1000?
Answered by
7
his first month's saving a = ₹200
2nd month = ₹250
sequence of his savings
200, 250, 300, 350......
common difference d= 250-200 = ₹50
no. of months n = 17
his total savings of 17 months will be
= n/2 *[ 2a + (n - 1)d ]
= (17/2)* [2(200) + (17-1)50]
= (17/2) * [400 + 800)
= 17 × 1200/2
= ₹10200
Answer: ₹10200
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