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Answer:
Given
- ABC is right angle with 90°
- BAC and ACB are base angles, so they are equal
BAC = x
= x + x + 90° = 180°
= 2x + 90° = 180°
= 2x = 180° - 90°
= 2x = 90°
= x = 90/2
= x = 45
answer : ABC = 90°
BCA = 45°
BAC = 45°
= 180
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ANSWER :-
- x = 45°
GIVEN :-
- ∆ABC is right angled at B. ∠ABC = 90°.
- AB = BC . Hence , ∆ABC is an isosceles triangle.
TO FIND :-
- Value of x.
TO KNOW :-
- Isoscales triangle has 2 sides equal.
- Angles opposite of equal sides are also equal. So, base angles of isoscales triangle is equal.
- Angle Sum Property :- Sum of all interior angles of a triangle is 180°.
HOW TO SOLVE ?
- As ∆ABC is isoscales triangle , base angles, ∠BAC and x are equal. We will use Angle Sum Property , and we will add all the interior angles .Sum of these angles is 180°. We will substitute ∠BAC as x ( both are equal ) and we will find the value of x.
SOLUTION :-
By angle Sum Property ,
∠ABC + ∠BAC + x = 180°
Substituting values , we get...
→ 90 + x + x = 180° (as ∠BAC = x)
→ 90 + 2x = 180°
→ 2x = 180 - 90
→ 2x = 90°
→ x = 45°
Hence , value of x is 45°.
VERIFICATION :-
As x = ∠BAC ,
∠BAC = 45°
Adding all angles , sum should be 180.
➔ ∠ABC + ∠BAC + x = 180
➔ 90 + 45 + 45 = 180
➔ 180 = 180 (verified)
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