What is apparent weight of body if lift is moving with acceleration a=g
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As the lift is moving with Uniform acceleration then Weight will be mg
If lift is moving with Increasing acceleration then weight will be Less than mg
If lift moves with decreasing velocity then Weight will be greater than mg
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the apparent weight of the man becomes less than the actual weight, when elevator is accelerating downwards. If a= g, then R = m (g-g) =0. It means apparent weight of a man in an elevator falling down freely with acceleration equal to acceleration due to gravity is zero.
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