Question

What is area of coloured square?

Answer 1

Answer:

Step-by-step explanation: answer:90

from fig1 i.e. the biggest triangle..

Tan(theta)=5/15 = 1/3

Now for smaller triangle "theta remains the same..so tan(theta) = 1/3 and hypotenuse is 5. Hence the adjecent side is 15/sqrt(10) and opposite side 5/sqrt(10)

Hence its area is 15/4.

Now required area=Area of big sqaure - 4(Area of biggest triangle) +4( area of smallest triangle)

=15*15- 4(0.5*5*15)+4(15/4)

=225-150+15

=90

Answer 2

Answer:$90$

Step-by-step explanation:

$Tan(theta)=5/15 = 1/3$

Now for smaller triangle "theta remains the same..so $tan(theta) = 1/3$and hypotenuse is $5$. Hence the adjacent side is $15/sq(10)$ and opposite side $5/sq(10)$

Hence its area is$15/4$.

Now required area=Area of big sq $- 4$ (Area of biggest triangle) $+4$( area of smallest triangle)

$=15*15- 4(0.5*5*15)+4(15/4)$

$=225-150+15$

$=90$

#SPJ2