Question

what is area of major sector ?

for shivani
and my friends​

Answer 1

Answer:

θ = l/r, where θ is in radians.

When the angle of the sector is 2π,

then the area of the sector (whole sector) is πr2. When the angle is 1, the area of the sector = πr2/2π = r2/2.

So,

when the angle is θ, area of the sector = θ × r2/2.

Hope this helps pal ☺☺

Good Night, Sleep tight

Answer 2

Answer:

Area of major sector is 274.89 units.

Explanation:

If r is the radius of a circle, then

area of circle is πr2 .

When we draw the sector BAC , where m∠BAC=45∘ ,

circle is divided in two parts - one is smaller sector BAC formed by arc BC , other is larger i.e. major sector BDCA . The angle formed by latter 360∘−45∘=315∘ .

As 360∘ comprises of area πr2 , a sector with an angle θ in degrees has an area of πr2/θ360 . In the given case r=AC=10 and as we want and area of major sector is π×10^2×315/360

Let us assume π = 3.1416 , hence area of major sector is 3.1416 × 100 ×315 /360 = 314.16×7/ 8 = 274.89.

꧁Hope its help you༄꧂