Math, asked by mazkhan123y, 3 months ago

what is area of this traingle and the peramete please solve quick.
all of them ​

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Answered by ruthvij1609
4

\large\boxed{Hello\:Mate}

1) → Perimeter = 8cm + 7cm + 6cm

  ⇒ Perimeter = 21cm

 

  height (h) = 6cm

  base (b) = 6cm

  → Area = \frac{bh}{2}

  ⇒ Area = \frac{6*6}{2}

  ⇒ Area = 18cm^{2}

2) → Perimeter = 6cm + 6cm + 3cm

   ⇒ Perimeter = 21cm

 

  height (h) = 5cm

  base (b) = 3cm

  → Area = \frac{bh}{2}

  ⇒ Area = \frac{3*5}{2}

  ⇒ Area = 15/2cm^{2}

3) → Perimeter = 6cm + 7cm + 8cm

   ⇒ Perimeter = 21cm

 

  height (h) = 6cm

  base (b) = 6cm

  → Area = \frac{bh}{2}

  ⇒ Area = \frac{6*6}{2}

  ⇒ Area = 18cm^{2}

4) → Perimeter = 5cm + 5cm + 5cm

   ⇒ Perimeter = 15cm

 

  height (h) = 4cm

  base (b) = 5cm

  → Area = \frac{bh}{2}

  ⇒ Area = \frac{5*4}{2}

  ⇒ Area = 10cm^{2}

5) → Perimeter = 5cm + 5cm + 4cm

   ⇒ Perimeter = 14cm

 

  height (h) = 4cm

  base (b) = 4cm

  → Area = \frac{bh}{2}

  ⇒ Area = \frac{4*4}{2}

  ⇒ Area = 8cm^{2}

6) → Perimeter = 8cm + 8cm + 8cm

   ⇒ Perimeter = 24cm

 

  height (h) = 7cm

  base (b) = 8cm

  → Area = \frac{bh}{2}

  ⇒ Area = \frac{8*7}{2}

  ⇒ Area = 28cm^{2}

7) → Perimeter = 4cm + 5cm + 6cm

   ⇒ Perimeter = 15cm

 

  height (h) = 5cm

  base (b) = 4cm

  → Area = \frac{bh}{2}

  ⇒ Area = \frac{4*5}{2}

  ⇒ Area = 10cm^{2}

8) → Perimeter = 8cm + 6cm + 6cm

   ⇒ Perimeter = 20cm

 

  height (h) = 5cm

  base (b) = 6cm

  → Area = \frac{bh}{2}

  ⇒ Area = \frac{6*5}{2}

  ⇒ Area = 15cm^{2}

9) → Perimeter = 7cm + 7cm + 7cm

   ⇒ Perimeter = 21cm

 

  height (h) = 6cm

  base (b) = 7cm

  → Area = \frac{bh}{2}

  ⇒ Area = \frac{7*6}{2}

  ⇒ Area = 21cm^{2}

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