Question

what is average kinetic energy of 1 mole of SO2 at 300k?

Answer 1

The answer of your question is "3741 J/mol"
You can easily findout it using the famous equation of 3/2 nRT

We know that one mole of any gas have average kinetic energy = 3/2nRT
Here "n" is the mole of the Gas which is 1 mole of SO2

"T" is representing the temperature which is given 300 k.
R is gas constant  which is equal to 8.314 JK^- 1 mole^-1 
So just put the values in equation

Average kinetiic energy of 1 Mole SO2 = 3/2 nRT = (3/2) 1*8.314* 300 =3741.3 J/mol  or 3741 J/mol  which is our answer.

Answer 2

Average Kinetic Energy for 1 mole of any gas  =  32nRT                                                     (n= no. of moles)

R  = 8.314 JK-1mole-1

T  =  300 K

n = 1 mole

so KE is given by = 32×1×8.314JK−1mole−1×300K= 3741 Jmole−1

mark as brainliest!!

cheers!!