Question

what is average of first n natural number?​

Answer 1

Answer:

The average of first n natural numbers = (n+1)/2. The average of squares of first n natural numbers = (n+1)(2n+1)/6. The average of cubes of first n natural numbers = n(n+1)2/4. The average of odd numbers from 1 to n = (last odd number+1)/2.

Answer 2

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⟹$average \: of \: n \: natural \: no. = \: \frac{(n + 1)}{(2)}$

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