Question

what is avogadro's number fine the number of molecules in (a) 56g of nitrogen gas (b) 88g of carbon dioxide (atomic mass of c=12u , n=14u , o=16 u )​

Answer 1

Explanation:

To Find -

• Number of molecules

a)

• 56g of N₂

Gram atomic mass (GAM) of N₂ = 14×2 = 28 g/mol

mole = mass ÷ GAM

→ 56/28

→ 2 mol

Number of molecules = mole × Nₐ

→ 2 × 6.022 × 10²³

→ 12.044 × 10²³

b)

• 88g of CO₂

Gram molecular mass (GMM) of CO₂ = 12 + 16×2 = 12+32 = 44 g/mol

mole = mass ÷ GAM

→ 88/44

→ 2 mol

Number of molecules = mole × Nₐ

→ 2 × 6.022 × 10²³

→ 12.044 × 10²³