what is bohar Bari skim in chemistry
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it's Bohr bury not bohar bari
Bohr–Bury rules of electronic configuration: Bohr and Bury simultaneously proposed the following rules for the distribution of electrons in different shells.
Rule 1: The maximum number of electrons that can be accommodated in a shell is equal to 2n2 where ‘n’ is the quantum number of the shell (i.e., the serial number of the shell from the nucleus).
Rule 2: Electrons may go into a new outer shell although the inner shells are incompletely filled.
Rule 3: The outermost shell cannot have more than 8 electrons and the next inner, i.e., the penultimate, shell cannot have more than 18 electrons.
Rule 4: Even if the capacity of the penultimate shell exceeds 8, it cannot have more than 8 electrons unless there are 2 electrons in the outermost shell. And it cannot have more than 9 electrons unless the anti–penultimate shell (i.e., the shell immediately preceding the penultimate shell) is completely filled. In such cases, the outermost shell can have more than 2
The rule is ocupation no. is given by 2n^2
So,k , n=l , 2X1^2=2
L, n=2, 2X2^2=8
M , n=3 ,2X3^2=18
N, n=4 , 2X4^2 =32
Bohr–Bury rules of electronic configuration: Bohr and Bury simultaneously proposed the following rules for the distribution of electrons in different shells.
Rule 1: The maximum number of electrons that can be accommodated in a shell is equal to 2n2 where ‘n’ is the quantum number of the shell (i.e., the serial number of the shell from the nucleus).
Rule 2: Electrons may go into a new outer shell although the inner shells are incompletely filled.
Rule 3: The outermost shell cannot have more than 8 electrons and the next inner, i.e., the penultimate, shell cannot have more than 18 electrons.
Rule 4: Even if the capacity of the penultimate shell exceeds 8, it cannot have more than 8 electrons unless there are 2 electrons in the outermost shell. And it cannot have more than 9 electrons unless the anti–penultimate shell (i.e., the shell immediately preceding the penultimate shell) is completely filled. In such cases, the outermost shell can have more than 2
The rule is ocupation no. is given by 2n^2
So,k , n=l , 2X1^2=2
L, n=2, 2X2^2=8
M , n=3 ,2X3^2=18
N, n=4 , 2X4^2 =32
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