What is bond lenght of X-T if X-X and T-T bond lengths are 198pm and 248pm?
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Answer:
198/Ea + 248/Eb + 9(Ea-Eb).
Explanation:
Since, the bond length of X-X is given as 198pm and the bond length of T-T is given as 248pm.
So, if we take the electronegativity value of X and T as Ea and Eb respectively. So, the value of radius of X will be 198/Ea and the value of radius of T is 248/Eb.
Now, we know the formulae of the bond length of X-T as radius of X + radius of T + 9(Ea-Eb) which will be having the value of 198/Ea + 248/Eb + 9(Ea-Eb).
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