Question

what is bond order in HCL​

Answer 1

Answer:

here is ur answer

Explanation:

Thus the predicted bond order of HCl is (2 − 0) ÷ 2 = 1. Because the σ bonding molecular orbital is closer in energy to the Cl 3p z than to the H 1s atomic orbital, the electrons in the σ orbital are concentrated closer to the chlorine atom than to hydrogen.

Answer 2

The bond order of Hcl is 1.

Explanation:

The Cl electrons residing up to 3s orbital (1s, 2s, 2px,2py,2pz,3s) area unit mostly stable than H negatron in 1s orbital and so they can't combine and kind bond. The 3p negatrons of Cl have comparable energy with the H electron and so area unit allowed to combine. However, since 3px and 3py orbitals have totally different symmetry than that of 1s orbital (if you think about coordinate axis because the internuclear axis), the sole doable commixture state of affairs is that the letter of the alphabet kind overlap between the 1s orbital of H and 3pz orbital of Cl. Note that each these orbitals area unit [*fr1] crammed and so allowed to create a bond. Therefore, the HCL molecule has eight pairs (1s, 2s, 2px,2py,2pz,3s,3px and 3py) of non-bonding (nb) electrons and one bonding (sigma) orbital having 2 electrons. The letter of the alphabet antibonding orbital are empty. The nb electrons would reside on Cl atom. Since the tendency of Cl is larger than the H atom, thus the letter of the alphabet bonding electrons can lie nearer to Cl than the H.