Chemistry, asked by kamleshbabriya1980, 8 months ago

what is boret oxidation number​

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Answered by upendrasingh1799906
0

Answer:

Oxidation state of Boron in borax is +3, as the formula is Na2B4O7. Each Na has +1 and each Oxygen has -2, suppose Boron has x. +2+4x -14 = 0. Hence x = +3.

Explanation:

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