Question

what is change in bond order during ionisation of no to no+​

Answer 1

Answer:

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Answer 2

Answer:

The bond order change from 2.5 to 3 during the ionization of NO to NO⁺.

Explanation:

Ionization is process of removing an electron from the outermost shell of atom in the gaseous state.

During the ionization of nitric oxide NO:

$NO$   $\longrightarrow$   $NO^{+}$    $+$     $e^{-}$

The one electron has been removed from the highest molecular orbital HOMO of the NO.

Bond order is the half of the difference between the electron in bonding molecular orbital and antibonding molecular orbital.

Molecular configuration of NO:

$(\sigma 1s)^{2}(\sigma ^{*}1s)^{2}(\sigma2s)^{2}(\sigma*2s)^{2}(\pi 2p_{x})^{2}(\pi 2p_{y})^{2}(\sigma2p_{z})^{2}(\pi ^{*}2p_{x})^{1}$

Bond order of NO $=\frac{1}{2}[10-5]$

                              $=2.5$

Molecular configuration of NO⁺:

$(\sigma 1s)^{2}(\sigma ^{*}1s)^{2}(\sigma2s)^{2}(\sigma*2s)^{2}(\pi 2p_{x})^{2}(\pi 2p_{y})^{2}(\sigma2p_{z})^{2}(\pi ^{*}2p_{x})^{0}$

Bond order of NO⁺ $=\frac{1}{2}[10-4]=3$

Therefore, after ionization of NO to NO⁺, the bond order change from 2.5 to 3.