what is change in momentum of a car weighting 1500 kg when its speed increases from 36 kg/hr to 72 km/hr uniformly ?
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Answer:
15000kgm/s
Explanation:
V final= 72 km/hr = 72×5/18= 20 m/s
V initial= 36 km/hr = 10 m/s
∆p= m(V final - V initial)
∆p= 1500(20-10)
∆p= 1500×10
∆p= 15000 kgm/s
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