What is co-efficient of friction for pulling a load of 400 kg by a force of 40 kg?
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Answer:
Given:
(i) Force required to pull the weight = 40 kg
(ii) Weight of the body = 400kg
(iii) The plane is horizontal
To find:
(i) Coefficient of friction
Solution:
We know that,
F = μN
where,
F = Force required to pull the object = 40 kgf = 400 N [Taking g = 10 m/s²]
N = Weight of the object
So, 400 = μ * m * g,
where,
m is the mass of the object = 400 kg.
So, 400 = μ * 400 * 10
⇒ μ = 400/4000
⇒ μ = 0.1
So, the coefficient of friction is 0.1
Step-by-step explanation:
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