Question

what is coefficient of terms in 12x square-17x+29​

Answer 1

Answer:

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STEP 1

:

Equation at the end of step 1

((22•3x2) - 17x) - 41 = 0

STEP 2

:

Trying to factor by splitting the middle term

2.1 Factoring 12x2-17x-41

The first term is, 12x2 its coefficient is 12 .

The middle term is, -17x its coefficient is -17 .

The last term, "the constant", is -41

Step-1 : Multiply the coefficient of the first term by the constant 12 • -41 = -492

Step-2 : Find two factors of -492 whose sum equals the coefficient of the middle term, which is -17 .

Answer 2

Answer:

The value of x= (17+i$\sqrt{1103\\}$ ) / 24 = 2.688 or x=(17-i$\sqrt{1103\\}$ ) / 24 = -1.271

Step-by-step explanation:

Use Sridharacharayas formula to solve.