Question

What is common difference of ap in which a 26-a 16=40

Answer 1

Answer:

Therefore, the common difference(d) is '4'.

Step-by-step explanation:

We know that the nth term of A.P is

$a_{n} =a+(n-1)d$

here 'a' is first term and 'd' is common difference.

Now the question is $a_{26} -a_{16} =40$ -----------(1)

Now we find the terms of $a_{26}$ and $a_{16}$

$a_{26}$ = $a+(26-1)d$

$a_{16}$ = $a+(16-1)d$

Put $a_{26}$ and $a_{16}$ values in equation(1).

⇒ $a+(26-1)d$ - $a+(16-1)d$ = 40

⇒ $a+25d-a-15d = 40$

⇒ $10d = 40$

⇒ $d = 4$

Therefore, the common difference(d) is '4'.