what is componendo dividendo rule give example question
Answers
Answered by
10
Componendo -:
a/b=c/d
By applying componendo -:
a+b/b=c+d/d i.e. we add the denominator in the numerator..
Dividendo-:
By applying dividendo -:
a/b=c/d
a/a-b = c/c-d i.e. we subtract the numerator in the denominator
a/b=c/d
By applying componendo -:
a+b/b=c+d/d i.e. we add the denominator in the numerator..
Dividendo-:
By applying dividendo -:
a/b=c/d
a/a-b = c/c-d i.e. we subtract the numerator in the denominator
sam8829:
please give a question of componendo and dividendo with solution
Answered by
6
Hey mate !!
Here's your answer :-)
QUESTION -:
Using the properties of proportion, solve for x, given x^4+1/2x^2=17/8
SOLUTION -:
(x^4+1)+2x^2/(x^4+1)-2x^2=17+8/17-8
[By applying componendo and dividendo]
(x^2+1)^2/(x^2-1)^2=25/9
x^2+1/x^2-1=5/3
[Taking square roots of both sides]
(x^2+1)+(x^2-1)/(x^2+1)-(x^2-1) = 5+3/5-3
[By applying componendo and dividendo]
2x^2/2 = 8/2 => x^2 = 4
x = 2, -2
Hope this helps☺☺
Here's your answer :-)
QUESTION -:
Using the properties of proportion, solve for x, given x^4+1/2x^2=17/8
SOLUTION -:
(x^4+1)+2x^2/(x^4+1)-2x^2=17+8/17-8
[By applying componendo and dividendo]
(x^2+1)^2/(x^2-1)^2=25/9
x^2+1/x^2-1=5/3
[Taking square roots of both sides]
(x^2+1)+(x^2-1)/(x^2+1)-(x^2-1) = 5+3/5-3
[By applying componendo and dividendo]
2x^2/2 = 8/2 => x^2 = 4
x = 2, -2
Hope this helps☺☺
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