Question

what is conditioner of this reaction
H2S+H2SO3→ S+H2O

Answer 1

Answer:

This is an oxidation-reduction (redox) reaction:

2 S-II - 4 e- → 2 S0

(oxidation)

SIV + 4 e- → S0

(reduction)

H2S is a reducing agent, H2SO3 is an oxidizing agent (synproportionation (comproportionation)).

Answer 2

Answer:

H2S is a reducing agent, H2SO3 is an oxidizing agent (synproportionation

Explanation:

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