what is conservation of momemtum
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◆ CONSERVATION OF MOMENTUM ◆
According to the law of conservation of momentum the total momentum of a system (or an object) remains constant if no net external unbalanced force acts on the system.
That is, momentum of a system , p = constant, if net external force acting on it is zero (i.e. F = 0).
◆ PROOF ◆
Consider a system consisting of two bodies A and B of masses and respectively.
Let these bodies are moving with velocities and .
Let > . Let these bodies collide with each other for a small interval of time .
At the time of collision, body A exerts a force F on body B and body B exerts equal and opposite force (-F) on body A.
Due to these forces, the momentum of the bodies changes.
Let and be the victories of body A and body B respectively after the collision.
Initial momentum of body A =
Initial momentum of body B =
Final momentum of body A =
Final momentum of body B =
Total momentum of the system before collision = +
Total momentum of the system after collision = +
Now, the rate of change of momentum of body A = change in momentum of body A/ Time Taken
= Final momentum - Initial momentum / Time Taken
=
According to Newton's second law of motion,
Force acting on body A = rate of change of momentum of body A
i.e. ,
Now, rate of change of momentum of body B = change in momentum of body B/Time Taken
=
According to Newton's second law of motion, Force acting on body B = rate of change of momentum of body B
i.e.
Or , Equating eqns. (1) and (2) , we get Or, i.e. Total momentum of the system ( i.e. bodies A and B ) before collision = Total momentum of the system ( i.e. bodies A and B ) After collision. This is the law of conservation of linear momentum.
According to the law of conservation of momentum the total momentum of a system (or an object) remains constant if no net external unbalanced force acts on the system.
That is, momentum of a system , p = constant, if net external force acting on it is zero (i.e. F = 0).
◆ PROOF ◆
Consider a system consisting of two bodies A and B of masses and respectively.
Let these bodies are moving with velocities and .
Let > . Let these bodies collide with each other for a small interval of time .
At the time of collision, body A exerts a force F on body B and body B exerts equal and opposite force (-F) on body A.
Due to these forces, the momentum of the bodies changes.
Let and be the victories of body A and body B respectively after the collision.
Initial momentum of body A =
Initial momentum of body B =
Final momentum of body A =
Final momentum of body B =
Total momentum of the system before collision = +
Total momentum of the system after collision = +
Now, the rate of change of momentum of body A = change in momentum of body A/ Time Taken
= Final momentum - Initial momentum / Time Taken
=
According to Newton's second law of motion,
Force acting on body A = rate of change of momentum of body A
i.e. ,
Now, rate of change of momentum of body B = change in momentum of body B/Time Taken
=
According to Newton's second law of motion, Force acting on body B = rate of change of momentum of body B
i.e.
Or , Equating eqns. (1) and (2) , we get Or, i.e. Total momentum of the system ( i.e. bodies A and B ) before collision = Total momentum of the system ( i.e. bodies A and B ) After collision. This is the law of conservation of linear momentum.
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