what is converse of mid point theorem ? and also prove
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A converse of a theorem is a statement formed by interchanging what is given in a theorem and what is to be proved. For example, the isosceles triangle theorem states that if two sides of a triangle are equal then two angles are equal.
GIVEN: ABC is a triangle
AD =BD
DE PARALLEL TO BC
TO PROVE: EA=EC
CONSTRUCTION: Draw CF parallel to AB
PROOF: In triangle EDA and EFC
DE parallel to BC
Hence DB = and parallel to FC
Therefore BDEF is a parallelogram ....
hence it is proved....
I HOPE IT HELPS U...
TQ.....
PLZZ MARK MY ANS AS BRAINLIST....
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Given: In ∆PQR, S is the midpoint of PQ, and ST is drawn parallel to QR.
To prove: ST bisects PR, i.e., PT = TR.
Construction: Join SU where U is the midpoint of PR.
Proof:
Statement
Reason
1. SU ∥ QR and SU = 12QR.
1. By Midpoint Theorem.
2. ST ∥QR and SU ∥ QR.
2. Given and statement 1.
3. ST ∥ SU.
3. Two lines parallel to the same line are parallel themselves.
4. ST and SU are not the same line.
4. From statement 3.
5. T and U are coincident points.
5. From statement 4.
6. T is the midpoint of PR (Proved).
6. From statement 5.
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