Math, asked by westevangelista, 19 days ago

what is correct for the quadratic function graphed

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Answers

Answered by AadiSri98
0

Answer:

C.

Step-by-step explanation:

The quadratic graph will be an upward parabola for y=ax^2+bx+c (a>0) and downward parabola for y= ax^2+bx+c (a<0).

An upward parabola can only have a minima and a downward parabola can only have a maxima.

Therefore, since the given graph is an upward parabola it will have a minima and the coefficient of x^2 will be positive.

Option C satisfies this condition for us.

Answered by chaudharyneetu749
0

Answer:

C

Step-by-step explanation:

General equation of parabola with Y-axis is

(x-h)² = 4a(y-k)

where (h,k) is the vertex of parabola and a is distance from focus

In this question the vertex is (0,-8)

so the equation we get of the parabola is

(x-0)² = 4(1/4)(y+8)

so the final equation we get is: y = x²-8

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