what is correct for the quadratic function graphed
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0
Answer:
C.
Step-by-step explanation:
The quadratic graph will be an upward parabola for y=ax^2+bx+c (a>0) and downward parabola for y= ax^2+bx+c (a<0).
An upward parabola can only have a minima and a downward parabola can only have a maxima.
Therefore, since the given graph is an upward parabola it will have a minima and the coefficient of x^2 will be positive.
Option C satisfies this condition for us.
Answered by
0
Answer:
C
Step-by-step explanation:
General equation of parabola with Y-axis is
(x-h)² = 4a(y-k)
where (h,k) is the vertex of parabola and a is distance from focus
In this question the vertex is (0,-8)
so the equation we get of the parabola is
(x-0)² = 4(1/4)(y+8)
so the final equation we get is: y = x²-8
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