What is cos(2sin−1x)?
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HERE IS YR ANS
Answer:
cos(2sin−1x)=1−2x2.
Explanation:
Let sin−1x=θ, so that, x=sinθ,|x|≤1,θ∈[−π2,π2].
Now, Reqd. Value =cos(2sin−1x)=cos2θ=1−2sin2θ=1−2x2
HOPE it helps......
HERE IS YR ANS
Answer:
cos(2sin−1x)=1−2x2.
Explanation:
Let sin−1x=θ, so that, x=sinθ,|x|≤1,θ∈[−π2,π2].
Now, Reqd. Value =cos(2sin−1x)=cos2θ=1−2sin2θ=1−2x2
HOPE it helps......
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