Question

what is cos? please follow me​

Answer 1

Answer:

Let the sum be x

Let the sum be x Amount after 2 year=Rs.4928

Let the sum be x Amount after 2 year=Rs.4928Rate=10% and 12%

Let the sum be x Amount after 2 year=Rs.4928Rate=10% and 12%Time=2 years

Let the sum be x Amount after 2 year=Rs.4928Rate=10% and 12%Time=2 yearsAmount=P(1+

Let the sum be x Amount after 2 year=Rs.4928Rate=10% and 12%Time=2 yearsAmount=P(1+ 100

Let the sum be x Amount after 2 year=Rs.4928Rate=10% and 12%Time=2 yearsAmount=P(1+ 100R

Let the sum be x Amount after 2 year=Rs.4928Rate=10% and 12%Time=2 yearsAmount=P(1+ 100R

Let the sum be x Amount after 2 year=Rs.4928Rate=10% and 12%Time=2 yearsAmount=P(1+ 100R )

Let the sum be x Amount after 2 year=Rs.4928Rate=10% and 12%Time=2 yearsAmount=P(1+ 100R ) t

Let the sum be x Amount after 2 year=Rs.4928Rate=10% and 12%Time=2 yearsAmount=P(1+ 100R ) t

Let the sum be x Amount after 2 year=Rs.4928Rate=10% and 12%Time=2 yearsAmount=P(1+ 100R ) t ⇒4928=x(1+

Let the sum be x Amount after 2 year=Rs.4928Rate=10% and 12%Time=2 yearsAmount=P(1+ 100R ) t ⇒4928=x(1+ 100

Let the sum be x Amount after 2 year=Rs.4928Rate=10% and 12%Time=2 yearsAmount=P(1+ 100R ) t ⇒4928=x(1+ 10010

Let the sum be x Amount after 2 year=Rs.4928Rate=10% and 12%Time=2 yearsAmount=P(1+ 100R ) t ⇒4928=x(1+ 10010

Let the sum be x Amount after 2 year=Rs.4928Rate=10% and 12%Time=2 yearsAmount=P(1+ 100R ) t ⇒4928=x(1+ 10010 )(1+

Let the sum be x Amount after 2 year=Rs.4928Rate=10% and 12%Time=2 yearsAmount=P(1+ 100R ) t ⇒4928=x(1+ 10010 )(1+ 100

Let the sum be x Amount after 2 year=Rs.4928Rate=10% and 12%Time=2 yearsAmount=P(1+ 100R ) t ⇒4928=x(1+ 10010 )(1+ 10012

Let the sum be x Amount after 2 year=Rs.4928Rate=10% and 12%Time=2 yearsAmount=P(1+ 100R ) t ⇒4928=x(1+ 10010 )(1+ 10012

Let the sum be x Amount after 2 year=Rs.4928Rate=10% and 12%Time=2 yearsAmount=P(1+ 100R ) t ⇒4928=x(1+ 10010 )(1+ 10012 )

Let the sum be x Amount after 2 year=Rs.4928Rate=10% and 12%Time=2 yearsAmount=P(1+ 100R ) t ⇒4928=x(1+ 10010 )(1+ 10012 )⇒4928=x×

Let the sum be x Amount after 2 year=Rs.4928Rate=10% and 12%Time=2 yearsAmount=P(1+ 100R ) t ⇒4928=x(1+ 10010 )(1+ 10012 )⇒4928=x× 100

Let the sum be x Amount after 2 year=Rs.4928Rate=10% and 12%Time=2 yearsAmount=P(1+ 100R ) t ⇒4928=x(1+ 10010 )(1+ 10012 )⇒4928=x× 100110

Let the sum be x Amount after 2 year=Rs.4928Rate=10% and 12%Time=2 yearsAmount=P(1+ 100R ) t ⇒4928=x(1+ 10010 )(1+ 10012 )⇒4928=x× 100110

Let the sum be x Amount after 2 year=Rs.4928Rate=10% and 12%Time=2 yearsAmount=P(1+ 100R ) t ⇒4928=x(1+ 10010 )(1+ 10012 )⇒4928=x× 100110 ×

Let the sum be x Amount after 2 year=Rs.4928Rate=10% and 12%Time=2 yearsAmount=P(1+ 100R ) t ⇒4928=x(1+ 10010 )(1+ 10012 )⇒4928=x× 100110 × 100

Let the sum be x Amount after 2 year=Rs.4928Rate=10% and 12%Time=2 yearsAmount=P(1+ 100R ) t ⇒4928=x(1+ 10010 )(1+ 10012 )⇒4928=x× 100110 × 100112

Let the sum be x Amount after 2 year=Rs.4928Rate=10% and 12%Time=2 yearsAmount=P(1+ 100R ) t ⇒4928=x(1+ 10010 )(1+ 10012 )⇒4928=x× 100110 × 100112

Let the sum be x Amount after 2 year=Rs.4928Rate=10% and 12%Time=2 yearsAmount=P(1+ 100R ) t ⇒4928=x(1+ 10010 )(1+ 10012 )⇒4928=x× 100110 × 100112

Let the sum be x Amount after 2 year=Rs.4928Rate=10% and 12%Time=2 yearsAmount=P(1+ 100R ) t ⇒4928=x(1+ 10010 )(1+ 10012 )⇒4928=x× 100110 × 100112 ⇒x=

Let the sum be x Amount after 2 year=Rs.4928Rate=10% and 12%Time=2 yearsAmount=P(1+ 100R ) t ⇒4928=x(1+ 10010 )(1+ 10012 )⇒4928=x× 100110 × 100112 ⇒x= 110×112

Let the sum be x Amount after 2 year=Rs.4928Rate=10% and 12%Time=2 yearsAmount=P(1+ 100R ) t ⇒4928=x(1+ 10010 )(1+ 10012 )⇒4928=x× 100110 × 100112 ⇒x= 110×1124928×100×100

Let the sum be x Amount after 2 year=Rs.4928Rate=10% and 12%Time=2 yearsAmount=P(1+ 100R ) t ⇒4928=x(1+ 10010 )(1+ 10012 )⇒4928=x× 100110 × 100112 ⇒x= 110×1124928×100×100

Let the sum be x Amount after 2 year=Rs.4928Rate=10% and 12%Time=2 yearsAmount=P(1+ 100R ) t ⇒4928=x(1+ 10010 )(1+ 10012 )⇒4928=x× 100110 × 100112 ⇒x= 110×1124928×100×100 =Rs.4000

Answer 2

Answer:

In a right angled triangle, the cosine of an angle is: The length of the adjacent side divided by the length of the hypotenuse. The abbreviation is cos. cos(θ) = adjacent / hypotenuse.

Step-by-step explanation: