Physics, asked by sindhusanjai24994, 9 months ago

what is cos square 300 degree + sin square 240 degree + tan 135 degree​

Answers

Answered by Anonymous
4

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Answered by amikkr
1

cos^{2} 300° + sin^{2} 240° + tan 135° = 0

Given -

cos^{2} 300° + sin^{2} 240° + tan 135°

To find - value of the above expression

Step by Step Explanation -

Basic concepts used

  • cos (360° - x°) = cos x°
  • sin (180° + x°) = -sin x°
  • tan (180° - x°) = -tan x°
  • cos^{2} (x) + sin^{2} (x) = 1

cos^{2} 300° + sin^{2} 240° + tan 135°
cos^{2} (360° - 300°) + sin^{2} (180° + 60°) + tan (180° - 45°)
⇒ {cos^{2} 60° + sin^{2} 60°} + tan (-45°)
⇒ 1 + (-1)
⇒ 0

cos^{2} 300° + sin^{2} 240° + tan 135° = 0

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