Math, asked by ameykamath2006, 2 months ago

what is (cosecθ+cotθ)^2

Answers

Answered by wadkeishita

0

Answer:

1+cos^2/1-cos^2

Step-by-step explanation:

[Cosec + cot]^2

= [1/Sin + cos/sin]^2

=[1+cos/sin]^2

=(1+cos) ^2/sin^2

=1+cos^2/sin^2

=1+cos^2/1-cos^2

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