Physics, asked by rubytiwari3789, 8 months ago

What is depletion region in case of a p-n junction? Explain the origin of junction barrier

potential. Discuss its dependence on the applied voltage, carrier concentration and type

of semiconductor.​

Answers

Answered by ItsUDIT
5

Explanation:

A depletion region is a natural feature of doping a semiconductor n-type and right next to it p-type. At the p-n junction (the border of the two types), the mobile electrons in the n-type (this is due to the excess electron provided by the n-dopant) diffuse across the junction, into the p-type area.

hope this will help you.

thank you

please mark as brainliest

Answered by ssonu43568
1

Depletion Region

Explanation:

  • A depletion region is a natural feature of doping a semiconductor n-type and right next to it p-type. At the p-n junction (the border of the two types), the mobile electrons in the n-type (this is due to the excess electron provided by the n-dopant) diffuse across the junction, into the p-type area. This then leaves the n-type area with a net positive charge, because the electron left
  • Holes (the majority charge-carriers in the p-type, created through doping with an element such as Indium (3 valence electrons)) can be said to 'diffuse' toward the n-type. (I think this is because of the electrons from the n-type causing the electrons in the p-type to repel away, and thus travel away from the n-type, filling existing holes and thus creating holes on their way, however this is not important)
  • In case of forward bias, p-type of the diode is connected to the positive terminal of the battery and n-type is connected to the negative terminal. When load is applied, negative terminal of the battery repels the electrons in the n side of the diode and they start moving towards the p-side.The more you apply voltage, more the width of depletion region is reduced and barrier potential reduces. At the same time, positive terminal also attracts the electrons moving from n side to p side. Once you cross the barrier potential(0.7 V in case of Si), current starts to flow in the opposite direction of the electrons. Here, current flows because of majority charge carriers( electrons in n-side and holes in p-side)
Similar questions