what is derivative of sin(x+y)
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• Derivative of sin(x+y) =
dy/dx = cos(x+y)/ 1-cos(x+y)
dy/dx = cos(x+y)/ 1-cos(x+y)
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5
Let y = sin(x+y)
sin^-1 (y) = x + y
On differentiating,
[1/(1-y²)] × (dy/dx) = 1 + (dy/dx)
(dy/dx) [1/(1-y²)] - (dy/dx) = 1
(dy/dx) [(1/(1-y²)) - 1 ] = 1
dy/dx = 1 / [(1/(1-y²)) - 1 ]
= (1-y²) / (1-1+y²)
dy/dx = (1-y²) / y²
-WonderGirl
sin^-1 (y) = x + y
On differentiating,
[1/(1-y²)] × (dy/dx) = 1 + (dy/dx)
(dy/dx) [1/(1-y²)] - (dy/dx) = 1
(dy/dx) [(1/(1-y²)) - 1 ] = 1
dy/dx = 1 / [(1/(1-y²)) - 1 ]
= (1-y²) / (1-1+y²)
dy/dx = (1-y²) / y²
-WonderGirl
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