Question

what is difference between displacement and double displacement reactions? write the equation for these?​

Answer 1

$\huge\mathfrak{Answer}$

Displacement Reaction

The reaction in which a highly reactive metal displaces the less reactive metals from its salt solution is called displacement reaction.

It can be written in the form of :-

$\boxed{\sf{</strong><strong>AB + C → AC + B</strong><strong>}}$

Ex:- Fe + CuSO4 → FeSO4 + Cu

Double Displacement Reaction

The reaction in which two reactants exchange their ions and one of the precipitate formed is insoluble in nature called double displacement reaction.

The precipitate is an insoluble product formed as a result of double decomposition reaction.

It is also known as neutralization reaction in case of interaction of an acid with base.

Double displacement reactions take the form:

$\boxed{\sf{</strong><strong>AB + CD → AD + CB</strong><strong>}}$

Ex:-

AgNO3 + NaCl → AgCl + NaNO3

BaCl2(aq) + Na2SO4(aq) → BaSO4(s) + 2 NaCl(aq)

Answer 2

$<v> In a displacement reaction, a more reactive element replaces a less reactive element from a compound.</p><p>For Example: CuSo4 (aq) + Zn (s) → ZnSO4 (aq) + Cu (s)</p><p>In a double displacement reaction, two atoms or a group of atoms switch places to form new compounds.</p><p></p><p>For Example: Na2SO4 (aq) + BaCl2 (aq) → BaSO4 (s) + 2NaCl (aq)</p><p>$