Question

what is difference, if 50 is subtracted from the sum of 3 consecutive prime numbers before 50 and 3 consecutive prime number after 50?​

Answer 1

Answer:

254

Step-by-step explanation:

= ((the sum of 3 consecutive prime numbers before) and (3 consecutive prime number after 50)) -50

sum of 3 consecutive prime numbers before 50:

41 + 43 + 47 = 131

sum of 3 consecutive prime numbers after 50:

53 + 59 + 61 = 173

Therefore,

= (131 + 173) - 50

= 304 - 50

= 254

Answer 2

The difference is 254.

Given - Number 50

Find - Difference

Solution - To solve this question, first enlist the consecutive numbers as mentioned. The perform addition. Now, take the sum and subtract 50 from it. The question with mentioned steps is solved below -

The 3 consecutive prime numbers before 50 = 41, 43, 47

The 3 consecutive prime numbers after 50 = 53, 59, 61

So, finding the sum of these numbers

Sum = 41 + 43 + 47 + 53 + 59 + 61

Performing addition

Sum = 304

Difference = 304 - 50

Performing subtraction

Difference = 254

Thus, the difference is 254.

#spj2