Math, asked by FazeelAnwar, 4 months ago

What is differentiation of sin inverse x/y with respect to x​

Answers

Answered by Anonymous
4

Answer:

sin(y) = sin(arcsin(x)) = x. Next, differentiate both ends of this formula. We apply the chain rule to the left end, remembering that the derivative of the sine function is the cosine function and that y is a differentiable function of x.

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Answered by VidishaRaj
48

.sin(y) = sin(arcsin(x)) = x. Next, differentiate both ends of this formula. We apply the chain rule to the left end, remembering that the derivative of the sine function is the cosine function and that y is a differentiable function of x.

...

y = arcsin(x) -1 x 1.

d dx sin(y) = d dx x

cos(y) dy dx = 1

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