what is differentiation of (sin x^3)^1/2
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differentiation of (sin x^3)^1/2
=>let sin x³ is u & x³ is v.
=>dy/dx=d/dx(sin x^3)^1/2
By chain method
=>dy/dx=d/du(u)½×d/dv(sinv)×d/dx(x)³
=>dy/dx=u-½×cosv×3x²
=>dy/dx=(sinx³)-½×cosx³×3x²
=>dy/dx=3x²cosx³/(sinx³)½
®®®®®®hope it help u®®®®®®
=>let sin x³ is u & x³ is v.
=>dy/dx=d/dx(sin x^3)^1/2
By chain method
=>dy/dx=d/du(u)½×d/dv(sinv)×d/dx(x)³
=>dy/dx=u-½×cosv×3x²
=>dy/dx=(sinx³)-½×cosx³×3x²
=>dy/dx=3x²cosx³/(sinx³)½
®®®®®®hope it help u®®®®®®
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