What is dimension whos perimeter is 14 cm and breadth is 448cm
Answers
AnswEr :-
- Breadth of the rectangle is 210cm.
CorrecTion :-
- What is the dimensions of the rectangle whose breadth is 14cm and perimeter is 448cm.
To Find :-
- length of the rectangle.
SoluTion :-
Let,
- Breadth of the rectangle be x
It is given that the perimeter of the rectangle is 448cm.
Formula for finding the perimeter of the rectangle is
2 (l + b)
Where,
- l = length
- b = breadth
According to question :-
2 (14 + x) = 448
→ 14 + x = 448/2
→ 14 + x = 224
→ x = 224 - 14
→ x = 210
Hence, the breadth of the rectangle is 210cm.
_____________________
Correct Question :
➥ What is the dimension of a rectangle whose breadth of a rectangle is 14 cm and perimeter is 448 cm
Answer :
➥ The length of a rectangle = 210 cm
Given :
➤ Breadth of a rectangle = 14 cm
➤ Perimeter of a rectangle = 448 cm
To Find :
➤ Length of a rectangle = ?
Required Solution :
❏ In the above Question, we are provided that the dimension of a rectangle whose breadth of a rectangle is 14 cm and perimeter is 448 cm that means There is a rectangle in which its breadth is 14 cm and the perimeter is 448 cm, and we need to find the length.
✒ To find the length of a rectangle, First we will assume the length of a rectangle be x m,Then, let's solve the solution on the basis of conditions given above.
Let ,
The length of a rectangle be "x"
We can find the length of a rectangle by using the formula of perimeter of a rectangle which says 2(l + b).
Here,
- l is the Length in cm.
- b is the Breadth in cm.
✎ So, let's find length (l) !
As we know that
⇛ Perimeter of rectangle = 2(l + b)
⇛ 448 = 2(x + 14)
⇛ 448 = 2x + 2 × 14
⇛ 448 = 2x + 28
⇛ 448 - 2x = 28
⇛ -2x = 28 - 448
⇛ -2x = -420
⇛ 2x = 420
⇛ x = 420/2
⇛ x = 210
║Hence, the length of a rectangle is 210 cm.║
Verification :
››› Perimeter of a rectangle = 448
››› 2(l + b) = 448
››› 2(210 + 14) = 448
››› 2(224) = 448
››› 448 = 448