Question

What is dipole moment?An electric dipole with dipole moment 4×10^-9 C m is aligned at an angle 30° with the direction of a uniform electric field at magnitude 5×10^4N/C . Calculate the magnitude of the torque acting on the electric dipole.

Answer 1

Dipole movement(P) is product of the separation of the ends of a dipole and the magnitude of the charges.

Torque= PE sin theta

= 4 × 10^-9 × 5 × 10^4 sin30°

= 4 × 10^-9 × 5 × 10^4 × 1/2

= 20 × 10^-5

= 2 × 10^-4 Nm

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Answer 2

Explanation:

$\Large{\red{\underline{\underline{\sf{\blue{Solution:}}}}}}$

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$\hookrightarrow$ Electric dipole moment, $\sf p\:=\:4\times 10^{-9}C\,m$

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$\hookrightarrow$ Angle made by p with a uniform electric field, $\sf \theta\:=\:30^{\circ}$

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$\hookrightarrow$ Electric field, $\sf E\:=\:5\times 10^4N\,C^{-1}$

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Torque acting on the dipole is given by the relation

$\hookrightarrow$ $\sf \tau\:=\:pE\sin \theta$

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$\sf \tau\:=\:4\times 10^{-9}\times 5\times 10^4\times \sin\,30$

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= $\sf ^{10}\cancel{20}\times 10^{-5}\times \dfrac{1}{\cancel{2}_1}$

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= $\sf 10^{-4}Nm$

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$\hookrightarrow$ Hence, the magnitude of torque acting on the dipole is $\sf{\pink{10^{-4}Nm}}$