what Is direction of force and displacement in a circular path?what is the work done in a circular path for (1/4)th of the complete circle?
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The direction of force is- inward(centripetal force)
displacement- 0
work done in a circular path for (1/4)th of the complete circle= 0
as work done= F×S×cos theta
theta= 90 degrees
therefore workdone= 0(at any point in a circle)
hope this answer helps
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